Clutch Prep is now a part of Pearson
Ch. 16 - Central Dogma & Gene RegulationWorksheetSee all chapters
All Chapters
Ch. 1 - Introduction to Microbiology
Ch. 2 - Disproving Spontaneous Generation
Ch. 3 - Chemical Principles of Microbiology
Ch. 4 - Water
Ch. 5 - Molecules of Microbiology
Ch. 6 - Cell Membrane & Transport
Ch. 7 - Prokaryotic Cell Structures & Functions
Ch. 8 - Eukaryotic Cell Structures & Functions
Ch. 9 - Microscopes
Ch. 10 - Dynamics of Microbial Growth
Ch. 11 - Controlling Microbial Growth
Ch. 12 - Microbial Metabolism
Ch. 13 - Photosynthesis
Ch. 15 - DNA Replication
Ch. 16 - Central Dogma & Gene Regulation
Ch. 17 - Microbial Genetics
Ch. 18 - Biotechnology
Ch. 21 - Viruses, Viroids, & Prions
Ch. 22 - Innate Immunity
Ch. 23 - Adaptive Immunity
Ch. 24 - Principles of Disease
Sections
Central Dogma
Introduction to Transcription
Steps of Transcription
Transcription Termination in Prokaryotes
Eukaryotic RNA Processing and Splicing
Introduction to Types of RNA
Genetic Code
Introduction to Translation
Steps of Translation
Review of Transcription vs. Translation
Prokaryotic Gene Expression
Review of Prokaryotic vs. Eukaryotic Gene Expression
Introduction to Regulation of Gene Expression
Prokaryotic Gene Regulation via Operons
The Lac Operon
Glucose's Impact on Lac Operon
The Trp Operon
Review of the Lac Operon & Trp Operon
Introduction to Eukaryotic Gene Regulation
Eukaryotic Chromatin Modifications
Eukaryotic Transcriptional Control
Eukaryotic Post-Transcriptional Regulation
Post-Translational Modification
Eukaryotic Post-Translational Regulation

Concept #1: Genetic Code

Concept #2: Genetic Code

Practice: The redundancy of the genetic code is a consequence of ______.

Practice: A particular triplet of bases in the template strand of DNA is 5′-AGT-3′. What would be the corresponding codon for the mRNA that is transcribed?

Practice: A particular triplet of bases in the coding sequence of DNA is AAA. The anticodon on the tRNA that binds the mRNA codon is ________.

Practice: Which of the following sequences of nucleotides are possible in the template strand of DNA that would code for the polypeptide sequence Phe–Leu–Ile–Val?

Practice: What amino acid sequence will be generated, based on the following mRNA codon sequence? 5′–AUG–UCU–UCG–UUA–UCC–UUG–3′