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Ch.6 Chemical Reactions & QuantitiesWorksheetSee all chapters
All Chapters
Ch.1 Matter and Measurements
Ch.2 Atoms and the Periodic Table
Ch.3 Ionic Compounds
Ch.4 Molecular Compounds
Ch.5 Classification & Balancing of Chemical Reactions
Ch.6 Chemical Reactions & Quantities
Ch.7 Energy, Rate and Equilibrium
Ch.8 Gases, Liquids and Solids
Ch.9 Solutions
Ch.10 Acids and Bases
Ch.11 Nuclear Chemistry
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Sections
Empirical Formula
Molecular Formula
Calculating Molar Mass
Mole Concept
Mass Percent
Stoichiometry
Limiting Reagent
Percent Yield

The Percent Yield determines how successful the product yield is in a chemical reaction. 

Percent Yield

Concept #1: Percent Yield

Example #1: Consider the following balanced chemical reaction:
2 C6H6 (l) + 15 O2 (g) → 12 CO2 (g) + 6 H2O (l)

If a 2.6 g sample of C6H6 reacted with excess O2 to produce 1.25 g of water, what is the percent yield of water?

Practice: What is the percent yield for a reaction in which 22.1 g Cu is isolated by reacting 45.5 g Zn with 70.1 g CuSO4?  

Zn (s) + CuSO4 (aq) → Cu (s) + ZnSO4 (aq)

Practice: Ammonia, NH3, reacts with hypochlorite ion, OCl, to produce hydrazine, N2H4. How many grams of hydrazine are produced from 115.0 g NH3 if the reaction has a 81.5% yield?  

2 NH3 + OCl → N24 + Cl + H2O

Practice: The reduction of iron (III) oxide creates the following reaction: 

Fe2O3 (s) + 3 H2 (g) → 2 Fe (s) + 3 H2O (g) 

If the above reaction only went to 75% completion, how many moles of Fe2O3 were require to produce 0.850 moles of Fe?