Clutch Prep is now a part of Pearson
All Chapters
Ch.1 Matter and Measurements
Ch.2 Atoms and the Periodic Table
Ch.3 Ionic Compounds
Ch.4 Molecular Compounds
Ch.5 Classification & Balancing of Chemical Reactions
Ch.6 Chemical Reactions & Quantities
Ch.7 Energy, Rate and Equilibrium
Ch.8 Gases, Liquids and Solids
Ch.9 Solutions
Ch.10 Acids and Bases
Ch.11 Nuclear Chemistry
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Solubility and Intermolecular Forces
Solutions: Mass Percent
Percent Concentrations
Parts per Million (ppm)
Solubility: Temperature Effect
Intro to Henry's Law
Henry's Law Calculations
Solution Stoichiometry
Electrolytes (Simplified)
The Colligative Properties
Boiling Point Elevation
Freezing Point Depression
Osmotic Pressure

Ever wonder how a mass amount such as moles can be converted into the volume amount of liters? Well, molarity serves as the bridge between moles and liters. 


Concept #1: Calculate Molarity

Example #1: Calculate the molarity of a solution prepared by dissolving 23.7 g NaOH in enough water to make 2.50 L of solution.

Concept #2: Using Molarity to Calculate Unknowns

Example #2: How many grams of Na3PO4 (MW: 163.94 g/mol) are present in 300.0 mL of a 0.550 M Na3POsolution?

Practice: What volume in (µL) of 0.125 M HBr contains 0.170 moles HBr?

Practice: Hypernatremia is a medical condition where a patient has high levels of sodium in their blood, and is the result of the body containing too little water. A patient has a measured sodium level of 165 mM. If 30.0 mL of their blood were drawn, what mass (in ng) of sodium would be present?

Practice: 2.64 grams of an unknown compound was dissolved in water to yield 150 mL of solution. The concentration of the solution was 0.075 M. What was the molecular weight of the substance?

Practice: A solution with a final volume of 750.0 mL was prepared by dissolving 30.00 mL of benzene (C6H6, density = 0.8787 g/mL) in dichloromethane. Calculate the molarity of benzene in the solution.