Practice: A compound that contains only carbon, hydrogen, and oxygen is composed of 48.64% C and 43.2% O by mass. What is the empirical formula of this compound?
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| Empirical Formula | 14 mins | 0 completed | Learn Summary |
| Molecular Formula | 20 mins | 0 completed | Learn |
| Combustion Analysis | 39 mins | 0 completed | Learn |
| Combustion Apparatus | 16 mins | 0 completed | Learn |
| Polyatomic Ions | 25 mins | 0 completed | Learn Summary |
| Naming Ionic Compounds | 11 mins | 0 completed | Learn |
| Writing Ionic Compounds | 7 mins | 0 completed | Learn |
| Naming Ionic Hydrates | 6 mins | 0 completed | Learn |
| Naming Acids | 18 mins | 0 completed | Learn |
| Naming Molecular Compounds | 6 mins | 0 completed | Learn |
| Balancing Chemical Equations | 15 mins | 0 completed | Learn |
| Stoichiometry | 23 mins | 0 completed | Learn Summary |
| Limiting Reagent | 21 mins | 0 completed | Learn Summary |
| Percent Yield | 20 mins | 0 completed | Learn Summary |
| Mass Percent | 4 mins | 0 completed | Learn Summary |
| Functional Groups in Chemistry | 11 mins | 0 completed | Learn |
The empirical formula gives the relative number of atoms.
Empirical Formula
Concept #1: Empirical Formula
Example #1: Determine the empirical formula of a compound that is 68.40% chromium and 31.60% oxygen.
Practice: Elemental analysis of a sample of an ionic compound showed 2.82 g of Na, 4.35 g of Cl, and 7.83 g of O. What is the empirical formula of the compound?
Practice: A compound composed of carbon, hydrogen, and chlorine contains 4.19 x 1023 hydrogen atoms. If 9.00 g of the compound also contains 55.0% chlorine by mass, what is the empirical formula?
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