Practice: Calculate the equilibrium constant for the following reaction at 25ºC.
Fe (s) + I2 (s) → Fe2+ (aq) + 2 I – (aq)
Given the following reduction potentials:
Fe2+(aq) + 2 e– →. Fe (s) E°red = – 0.45 V
I2 (s) + 2 e– →. 2 I – (aq) E°red = + 0.54 V